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A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the​ exam, scores are normally distributed with mu equals516. The teacher obtains a random sample of 2000 ​students, puts them through the review​ class, and finds that the mean math score of the 2000 students is 521 with a standard deviation of 111. Complete parts​ (a) through​ (d) below. a) State the null and alternative hypothesis. Let u be the mean score.

Respuesta :

Answer:

Null hypothesis : [tex]H_0:\mu = 516[/tex]

Alternate hypothesis :[tex]H_a:\mu> 516[/tex]

Step-by-step explanation:

Given : [tex]\mu = 516\\x=521\\\sigma = 111\\n = 2000[/tex]

To Find :  State the null and alternative hypothesis.

Solution:

We are given that A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam.

So, claim is increase in he scores of students on the math portion of a college entrance exam.

So,

Null hypothesis : [tex]H_0:\mu = 516[/tex]

Alternate hypothesis :[tex]H_a:\mu> 516[/tex]