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This homework will be due when you come to lab. Two students are pushing identical crates across a frictionless floor. The crates are initially at rest. Bing applies a horizontal force of 23 N to his crate. Bob, who is shorter than Bing, pushes on his crate at an angle of 33° below the horizontal, also with a force of 23 N. Find the ratio of the masses of the two crates if Bing’s crate is moving at twice the speed of Bob’s crate after they have traveled a distance of 33.5 m

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Chenk13

Answer:

0.459

Explanation:

Energy

1. [tex]E = \frac{1}{2} mv^{2}[/tex]

2.[tex]E = Fx[/tex]

Combining 1 and 2:

3.[tex]m = \frac{2Fx}{v^{2} }[/tex]

Using 3 to form the ratio:

[tex]\frac{m_1}{m_2} = \frac{F_1}{F_2} \frac{v_2^{2} }{v_1^{2} }[/tex]

Given in the question:

[tex]v_1 = 2v_2[/tex]

[tex]F_2 = F_1 sin(33)[/tex]

Result:

[tex]\frac{m_1}{m_2} = \frac{1}{4sin(33)}[/tex]

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