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An ideal gas in a cylinder occupies a volume of 0.065 m3 at room temperature (T = 293 K). The gas is confined by a piston with a weight of 100 N and an area of 0.65 m2. The pressure above the piston is equal to one atmosphere (atm = 1.013x105 Pa). The piston is free to move up and down. 1) What is the magnitude of the net force on the piston? zero 50 N 100 N 2) Briefly explain your answer.

Respuesta :

Answer:

zero

Explanation:

There are three forces acting on the piston

1. force due to atmospheric pressure = F1 downward

2. force due to gaseous pressure = F2 upward

3. force due to the weight placed on the piston = F3 = mg downward

As the piston is in equilibrium condition, so the net force on the piston is zero.

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