Answer:
Margin of error =z-score value for chosen confidence level×population standard deviation
Assuming a 95% confidence level , then
z=1.96
standard deviation=5.75
Margin of error= 1.96×5.75=11.27
Answer:
Step-by-step explanation:
Given that there is a sample statistic for a population. Population std deviation sigma is given as 5.75.
Margin of error = z critical value * std error
For standard error we must know the sample size n.
Std error = [tex]\frac{\sigma}{\sqrt{n} } =\frac{5.75}{\sqrt{n} }[/tex]
Margin of error = Z critical * std error =[tex]1.96*\frac{5.75}{\sqrt{n} }[/tex] for 95%
=[tex]2.58*\frac{5.75}{\sqrt{n} }[/tex] for 99%
Z critical = 1.96 for 95% and 2.58 for 99%
Hence margin of error =
