Answer:
he can expect to lose 0.5$
Step-by-step explanation:
To solve this problem we must calculate the expected value of the game.
If x is a discrete random variable that represents the gain obtained when rolling a dice, then the expected value E is:
[tex]E =\sum xP (x)[/tex]
When throwing a dice the possible values are:
x: 1→ -$9; 2→ $4; 3→ -$9; 4→ $8; 5→ -$9; 6→ $12
The probability of obtaining any of these numbers is:
[tex]p=\frac{1}{6}[/tex]
The gain when obtaining an even number is twice the number.
The loss to get an odd number is $ 9
So the expected gain is:
[tex]E=-9*\frac{1}{6}-9*\frac{1}{6}-9*\frac{1}{6} + 4*\frac{1}{6} + 8*\frac{1}{6} + 12*\frac{1}{6}\\\\E =-27*\frac{1}{6} + 24*\frac{1}{6}\\\\E=-3*\frac{1}{6}\\\\E=-$0.5[/tex]
