An urn contains balls numbered 1 through 20. A ball is chosen, returned to the urn, and a second ball is chosen. The probability that the first and second balls will be a 8 is [tex]\frac{1}{400}[/tex]
Further explanation
A random variable, random quantity, aleatory variable, or stochastic variable is described as a variable that the values depend on outcomes of a random phenomenon. The formal mathematical treatment of random variables is a topic in probability theory
There are two types of random variables such as discrete and continuous. Random variables can assume only a countable number of values are called discrete. Whereas the random variables that can take on any of the countless number of values in an interval are called continuous.
The chance of the first ball being a [tex]8[/tex] is [tex]\frac{1}{20}[/tex]. Similarly, the chance of the second being a [tex]8[/tex] is [tex]\frac{1}{20}[/tex].
To find the chance if both happening, muliply the two.
[tex]\frac{1}{20}[/tex] * [tex]\frac{1}{20}[/tex] = [tex]\frac{1}{400}[/tex]
Because since you return it [tex]\frac{1}{20}[/tex] again and those combined make [tex]\frac{1}{400}[/tex] since [tex]20 * 20= 400[/tex]
Learn more
- Learn more about urn https://brainly.com/question/7153497
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Answer details
Grade: 9
Subject: mathematics
Chapter: probability
Keywords: urn, balls, probability, second, first
