Answer:
Option C [tex]\frac{1}{8*8*8*8*8*8*8*8}[/tex]
Step-by-step explanation:
we have
[tex](8^{2})^{-4}[/tex]
Remember that
[tex](a)^{-b} = \frac{1}{a^{b}}[/tex]
[tex](a^{b})^{c}=(a)^{b*c}[/tex]
therefore
[tex](8^{2})^{-4}=(8)^{-4*2}=(8)^{-8}[/tex]
[tex](8)^{-8} = \frac{1}{8^{8}}[/tex]
[tex]\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}[/tex]
