Answer:
Step-by-step explanation:
Given that a survey found that women's heights are normally distributed with mean 63.4 in and standard deviation 2.2 in.
Let X be the random variable representing women heights.
P(58<X<80)
Z for 58 = -2.454
Z for 80 = 7.545
P(-2.454<Z<7.545) = 0.4945+0.5=0.9945