Answer:
0 < x ≤ 12 and 0 < y ≤ 36
Step-by-step explanation:
Here, x represents the number of female gazelles and y represents the number of male gazelles.
The zoo only has room for 12 female gazelles.
∵ The number of rooms must be more than or equal to the total female gazelles ,
12 ≥ x
Also, number of animals can not be negative,
And, it must be greater than 0.
⇒ 0 < x ≤ 12,
⇒ 3(0) < 3x ≤ 3(12)
⇒ 0 < 3x ≤ 36
∵ Number of males gazelles = 3 × number of female gazelles
⇒ y = 3x
⇒ 0 < y ≤ 36
Hence, the constraints to represent a thriving population of gazelles at the zoo are,
0 < x ≤ 12,
0 < y ≤ 36
Answer:
The constraint which represent a thriving population of gazellea at the zoo is:
0 < x ≤ 10 and 0 < y ≤ 30.
Step-by-step explanation:
Let x = the number of female gazelles and y = the number of male gazelles.
Now, it is given that:
The group needs two times more males than females to thrive, and the zoo only has room for 12 female gazelles.
This means that:
0 < x ≤ 10
( Because there are no room for more than 12 gazelles )
Also,
y= 3x
Since,
x>0
This means that: 3x>0
i.e. y>0
and x ≤ 12
i.e. 2x ≤ 30
i.e. y ≤ 30
Hence, the constraints which represent a thriving population of gazelles
at the zoo is:
0 < x ≤ 12 and 0 < y ≤ 30.
