contestada

A water tank has the shape of an inverted circular cone with base radius 2m and height 4m. If water is being pumped into the tank at a rate of 2 m3 / min, find the rate at which the water level is rising when the water is 3 m deep.

Respuesta :

The rate of rising water level can be calculated by the differentiation of volume formula. The rate of rising water level is 0.48 m/min.

The shape of a water tank is a circular cone, so the volume can be calculated by:

[tex]V = \dfrac {\pi r^2 h}3[/tex]

Where,

 

[tex]V[/tex] = volume,

[tex]r[/tex] = base radius,

[tex]h[/tex] = height or water level

To calculate the rate differentiate both sides with respect to time. Assume radius [tex]r[/tex] as constant.

[tex]\dfrac {dV}{dt} = \pi r^2(\dfrac {dh}{dt})\dfrac 13[/tex]

Given here,  

[tex]\dfrac {dV}{dt} = 2m^3/min\\\\r = 2m[/tex]

Put the values in the formula,

[tex]\ \ \ 2 = \pi 2^2\times {\dfrac {dh}{dt }\times \dfrac 13}\\\\\dfrac {dh}{dt} = 0.48\rm \ m/min[/tex]

Therefore, the rate at which of rising water level is 0.48 m/min.

Learn more about the rising water level problems,

https://brainly.com/question/13806595