Explanation:
F=Bqv (in magnetic field)
9.5*10^-15=(5.2*10^-19)(2.2*10^-1)*v
solve for v.
Answer : The speed of particle is [tex]8.3\times 10^4m/s[/tex]
Explanation :
Magnetic force : It is defined as when a charged particle moves in magnetic field, then force is exerted on the moving charged particle. In this the force is perpendicular to both the velocity of the charge and the magnetic field.
Formula used :
[tex]F=qvB[/tex]
where,
F = magnetic force = [tex]9.5\times 10^{-15}N[/tex]
q = charge = [tex]5.2\times 10^{-19}C[/tex]
v = velocity of charge = ?
B = magnetic field strength = [tex]2.2\times 10^{-1}tesla[/tex]
Now put all the given values in the above formula, we get:
[tex]F=qvB[/tex]
[tex]9.5\times 10^{-15}N=(5.2\times 10^{-19}C)\times v\times (2.2\times 10^{-1}tesla)[/tex]
[tex]v=8.3\times 10^4m/s[/tex]
Therefore, the speed of particle is [tex]8.3\times 10^4m/s[/tex]
