Answer:
The coordinates of Jedds house are (-7 , -2)
Step-by-step explanation:
* Lets explain how to solve the problem
- If point (x , y) divide the distance between the two points
[tex](x_{1},y_{1})[/tex] and [tex](x_{2},y_{2})[/tex] at the ratio
[tex](m_{1}:m_{1})[/tex], then
[tex]x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}[/tex] and
[tex]y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}[/tex]
* Lets solve the problem
∵ Hollis house is located at (-1 , 4)
∴ [tex](x_{1},y_{1})[/tex] = (-1 , 4)
∵ She can walk in a straight line to get to Jedds house
∵ The restaurant is located at (-3 , 2) and partitions the way from
Hollis house to Jedds house by a ration of 1 : 2
∴ (x , y) = (-3 , 2)
∴ [tex](m_{1}:m_{1})[/tex] = 1 : 2
- Lets consider that Jedds house is located at [tex](x_{2},y_{2})[/tex]
∴ [tex]-3=\frac{-1(2)+x_{2}(1)}{1+2}[/tex]
∴ [tex]-3=\frac{-2+x_{2}}{3}[/tex]
- Multiply both sides by 3
∴ [tex]-9=-2+x_{2}[/tex]
- Add 2 for both sides
∴ [tex]-7=x_{2}[/tex]
∴ [tex]2=\frac{4(2)+y_{2}(1)}{1+2}[/tex]
∴ [tex]2=\frac{8+y_{2}}{3}[/tex]
- Multiply both sides by 3
∴ [tex]6=8+y_{2}[/tex]
- Subtract 8 for both sides
∴ [tex]-2=y_{2}[/tex]
∴ The coordinates of Jedds house are (-7 , -2)
Answer:
(-7 , -2)
Step-by-step explanation:
The above answer is correct
