Respuesta :
Explanation:
It is given that,
Mass of the runner, m₁ = 60 kg
Speed of runner, v₁ = 11 m/s
Mass of cheetah, m₂ = 60 kg
Speed of cheetah, v₂ = 33 m/s
Kinetic energy of runner, [tex]E_r=\dfrac{1}{2}m_1v_1^2[/tex]
[tex]E_r=\dfrac{1}{2}\times 60\times (11)^2=3630[/tex]........(1)
Kinetic energy of cheetah, [tex]E_c=\dfrac{1}{2}m_2v_2^2[/tex]
[tex]E_c=\dfrac{1}{2}\times 60\times (33)^2=32670\ J[/tex]..............(2)
From equation (1) and (2), it is clear that
[tex]E_c= 9\times E_r[/tex]
So, the kinetic energy of the cheetah is nine times that of human runner. Hence, this is the required solution.
Answer:
The kinetic energy of the cheetah exceed by the 9 times of the runner.
Explanation:
Given that,
Mass of runner = 60 kg
Velocity of runner = 11 m/s
Mass of cheetah = 60 kg
Velocity of cheetah = 33 m/s
We need to calculate the kinetic energy of the cheetah
Using formula of kinetic energy
[tex]K.E=\dfrac{1}{2}mv^2[/tex]
Kinetic energy of runner
[tex]K.E_{r}=\dfrac{1}{2}m_{r}v_{r}^2[/tex]....(I)
Kinetic energy of cheetah
[tex]K.E_{c}=\dfrac{1}{2}m_{c}v_{c}^2[/tex]....(II)
From equation (I) and (II)
[tex]\dfrac{K.E_{r}}{K.E_{c}}=\dfrac{\dfrac{1}{2}m_{r}v_{r}^2}{\dfrac{1}{2}m_{c}v_{c}^2}[/tex]
[tex]K.E_{c}=\dfrac{\dfrac{1}{2}m_{c}v_{c}^2}{\dfrac{1}{2}m_{r}v_{r}^2}\timesK.E_{r}[/tex]
Put the value into the formula
[tex]K.E_{c}=\dfrac{\dfrac{1}{2}\times60\times(33)^2}{\dfrac{1}{2}\times60\times(11)^2}\timesK.E_{r}[/tex]
[tex]K.E_{c}=9K.E_{r}[/tex]
Hence, The kinetic energy of the cheetah exceed by the 9 times of the runner.
