Three friends went to the fair. Michelle ate three hot dogs, one pretzel, and two snow cones. She spent $25. Amanda ate two hot dogs, three pretzels, and three snow cones. She spent $30. Lucas ate two hot dogs, two pretzels, and four snow cones. He spent $25. Which system of equations matches the friends' night at the fair?

2x + y + 3z = 25
2x + 3y + 3z = 30
2x + 2y + 4z = 25
3x + y + 2z = 25
2x + 3y + 3z = 30
2x + 2y + 4z = 25
3x + y + 2z = 25
3x + 2y + 3z = 30
2x + 2y + 4z = 25
3x + y + 2z = 25
2x + 3y + 3z = 30
2x + 4y + 2z = 25

Question

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Respuesta :

bhartin bhartin · Answer 1 · 2019-08-07T16:02:14+02:00

Answer:

the answer to your question is 2x + 3y + 3z = 30

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lublana lublana · Answer 2 · 2019-08-23T12:42:29+02:00

Answer:

b.[tex]3x+y+2z=25[/tex]

[tex]2x+3y+3z=$30[/tex]

[tex]2x+2y+4z=$25[/tex]

Step-by-step explanation:

We are given that three friends went to fair

Let cost of hot dog=x

Cost of pretzel=y

Cost of snow cone=z

Michelle ate 3 hot dog,one pretzel and two snow cones and spent $25.

Therefore, according to question the equation is

[tex]3x+y+2z=25[/tex]

Amanda ate two hot dog, three pretzel and three snow cones and spent $30

Therefore,the equation is

[tex]2x+3y+3z=$30[/tex]

Lucas ate two hot dogs,two pretzel and four snow cones and spent $25.

Therefore, the equation is

[tex]2x+2y+4z=$25[/tex]

Hence, option b is true.