Answer:
Q = 424523.22 kw
Explanation:
[tex]\rho =7833 kg/m[/tex]
k = 48.9 W/m - K
c = 0.115 KJ/kg- K
[tex]\alpha = 3.91*10^{-6} m^2/s[/tex]
[tex]T_s = 285 degree celcius[/tex]
T_∞ = 35 degree celcius
velocity of air stream = 15 m/s
D = 40 cm
L = 200 cm
mass flow rate[tex] \dot m = \rho AV = 7833 *\frac{\pi}{4} 0.4^2*15[/tex]
[tex]\dot m = 14764.85 kg/s[/tex]
[tex]A_s = \pi DL = \pi 0.4*2 = 2.513 m^2[/tex]
[tex]Q = \dot m C \Delta T = h A_s \Delta T[/tex]
[tex]\dot m C \Delta T = h A_s \Delta T[/tex]
solving for h
[tex]h = \frac{14764.85*0.115*(285-35)}{2.513*(285-35)}[/tex]
h = 675.6 kw/m^2K
[tex]Q = h A_s\Delta T[/tex]
Q = 675.6*2.513*(285-35)
Q = 424523.22 kw
