Answer:
Q = 0.00017597 m3/sec
Explanation:
given data:
temperature of water 15.6 degree celcius
diameter = 10cm =0.1 m
dynamix viscosity of water = .0011193 kg/m sec at 15.6 degree celcius
density of water at 15.6 degree = 999.07 kg/m3
for laminar flow REYNOLD NUMBER < 2000
maximum flow rate =area*velocity
Reynold number [tex]Re = \frac{\rho vd}{\mu}[/tex]
[tex]v = \frac{Re \mu}{\rho d}[/tex][tex]v = \frac{2000*0.00011193}{999.07 *0.1}[/tex]
v = 0.022406 m/sec
[tex]Q =\frac{\pi}{4} d^2 v[/tex]
where Q is flow expressed in m^3/s
[tex]Q =\frac{\pi}{4} *0.1^2 *0.022406[/tex]
Q =0.00017597 m3/sec
