Answer:
W = 377.312 KJ/kg
P =1131.937 KW
Explanation:
[tex]\dot m = 3 kg/s[/tex]
V_1 =15m/s
P_1 = 1200kPa
T_1 = 350 DEGREE C
For above value , and from super heated tables H_1 = 3153.3 Kj/kg
P_2 = 100kPa
T_2 = 150 degree C
For above value , and from super heated tables H_2 = 2776.1 Kj/kg
v_2 = 0
from energy equation
[tex]Q + H_1 +\frac{v_1^2}{2} = W + H_2 +\frac{v_2^2}{2}[/tex]
[tex]H_1 +\frac{v_1^2}{2} = W + H_2[/tex] { V_2 = 0, Q =0}
[tex]3153.3 + \frac{15^2}{2} = 2776.1 +W[/tex]
W = 377.312 KJ/kg
power is given as
[tex]P = \dot m * w[/tex]
P = 3*377.312 = 1131.937 KW