Answer:
Circular tube
Explanation:
Now for better understanding lets take an example
Lets take
Diameter of solid bar= [tex]4\sqrt{2}[/tex] cm
Outer diameter of tube =6 cm
Inner diameter of tube=2 cm
So from we can say that both tubes have equal cross sectional area.
We know that buckling load is given as [tex]P = \dfrac{\pi ^2EI}{L_e^2}[/tex]
If area moment of inertia(I) is high then buckling load will be high.
We know that area moment of inertia(I)
For circular tube [tex]I = \dfrac{\pi }{64}(D_o^4-D_i^4)[/tex]
For circular bar [tex]I = \dfrac{\pi }{64}D^4[/tex]
Now by putting the values
For circular tube [tex] I=62.83 cm^4[/tex]
For circular bar [tex] I=50.26 cm^4[/tex]
So we can say that for same cross sectional area the area moment of inertia(I) is high for tube as compare to bar.So buckling load will be higher in tube as compare to bar.
