Answer:
original diameter is 0.417 inch
Explanation:
given,
oxygen free copper rod undergoes 40 percent cold working.
final diameter (d₂) = 0.25 inch
original diameter of copper rod = d₂ = ?
[tex]\% reduction =\dfrac{ reduction\ in\ dia }{original\ dia}[/tex]
[tex]\% reduction =\dfrac{ d_1-d_2}{d_1}[/tex]
[tex]0.4 =\dfrac{ d_1-0.25}{d_1}\\0.6d_1 = 0.25\\d_1 = 0.417[/tex]
hence, original diameter is 0.417 inch
