Answer:
a) 0.005s
b) F = -520 N , this is taking the direction into account.
Explanation:
let d be the distance covered by the hummer and nail, a be the acceleration of the hummer and nail
a) m = 0.650 kg
Vi = 4.00 m/s
d = 0.01 m
(Vf)^2 = (Vi)^2 + 2(a)(d)
0 = (4)^2 + 2(a)(0.01)
a = -800 m/s^2
then:
Vf = Vi + at
0 = 4 + (-800)t
t = 0.005s
Therefore, the impact lasted for 0.005s.
b) the average force is given by:
F = ma = (0.650)(-800) = - 520 N
Therefore, the magnitude of the average force is 520 N.
