Answer:
a) The image is formed 10.62 cm behind the mirror.
b) The image will be 1.78 cm and the negative sign shows that the height will upside down.
Explanation:
for f is the focal length of the mirror, u is the distance from the mirror to the object, v is the distance from the mirror to the image and r is the radius of curvature.
the focal length is given by:
f = -r/2 = -(12.8)/2 = -6.4 cm
a) the mirror formula:
1/f = 1/v + 1/u
1/v = 1/f - 1/u
= 1/(-6.4) - 1/(-16.1)
= -0.094138
v = -10.62 cm
Therefore, the image is formed 10.62 cm behind the mirror.
b) let m be the magnification of the mirror and h1 be the height of the image, then:
m = -v/u = h1/h
-v/u = h1/h
h1 = (-v/u)(h)
= -(-10.62/-16.1)(2.70)
= - 1.78 cm
Therefore, the image will be 1.78 cm and the negative sign shows that the height will upside down.
