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What is the slope of the line with the following equation?

[tex]2x+3y=2[/tex]

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QUESTION

Your equation is 2x+3y=2 and you need to find the slope.

EXPLANATION

There are many ways to find the slope with an equation like this. I'm going to change the equation into slope-intercept form.

Slope-intercept form is formatted like this:

y=mx+b

m represents the slope. The first thing you need to do is leave 3y alone to change the equation into slope-intercept form. That means you need to subtract 2x from both sides.

[tex]2x+3y=2 \rightarrow 3y=2-2x\ or\ 3y=-2x-2[/tex]

The next thing you need to do is leave y alone, just like the slope-intercept form example. To leave y alone, you need to divide 3y by 3.

[tex]\frac{3y}{3}=\frac{-2x-2}{3} \\ \\ y=-\frac{2}{3}x-\frac{2}{3}[/tex]

Now the equation has been changed to slope-intercept form. In the equation, m has been replaced by [tex]-\frac{2}{3}[/tex], which means that is your answer.

Answer: [tex]-\frac{2}{3}[/tex]

Answer:

slope = - [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + 3y = 2 into this form

Subtract 2x from both sides

3y = - 2x + 2 ( divide all terms by 3 )

y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{2}{3}[/tex] ← in slope- intercept form

with slope m = - [tex]\frac{2}{3}[/tex]