Answer:[tex]\frac{15}{56}[/tex]
Step-by-step explanation:
We have to select george but not nina with two other people
No. of ways selecting 2 two people knowing Geroge will be the third one is
[tex]^6C_2[/tex] (beacuse we have to exclude Nina)
And total no of ways of selecting 3 people out of 8 people is [tex]^8C_3[/tex]
Therefore the required Probability is [tex]\frac{^6C_{2}}{^8C_{3}}[/tex]
=[tex]\frac{15}{56}[/tex]
