Answer:
D. 200 kgm/s
Explanation:
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. Therefore, the final momentum of the blue and green train combined is 200 kgm/s.
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s then the final momentum of the blue and green trains combined would be 200 kgm/s, therefore the correct option is option D.
It is a type of Collison for which the momentum, as well as the kinetic energy after and before the collision, is constant. there is no loss of energy in a perfectly elastic collision.
By using the law of conservation of momentum
momentum before collision = momentum after the collision
The initial momentum of the blue train + initial momentum of green train = final momentum of the blue train + final momentum of the green train
By substituting the respective values
combined initial momentum = combined final momentum
50×4 + 30×0 = the final momentum of the both blue train and the green train
the final momentum of the both blue train and the green train would be 200 kgm/s, therefore the correct option is D.
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