Given that I0=10−12 watts/meter2, what is the intensity of a sound for which the decibel level of the sound measures 148? Round off your answer to three decimal places.

Respuesta :

Answer:

Sound intensity is 630.95 W/m².

Explanation:

It is given that,

The decibel level of the sound, I(dB) = 148

Sound intensity level is given by :

[tex]I(dB)=10log_{10}(\dfrac{I}{I_o})[/tex]

[tex]148 = 10\log_{10}(\dfrac{I}{10^{-12}})[/tex]

[tex]14.8 = log_{10}(\dfrac{I}{10^{-12}})[/tex]

After solving above equation using calculator we get,

[tex]I=630.95\ W/m^2[/tex]    

So, the intensity of a sound is 630.95 W/m². Hence, this is the required solution.