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Assuming the pendulum is on the Earth and g = 10m/s2, what is the period if the length is 10 m?
A. 2π s
B. 1 s
C. π s
D. π/2 s

Respuesta :

MathPhys

Answer:

A. 2π s

Explanation:

Period of a pendulum is:

T = 2π √(L/g)

Given L = 10 m and g = 10 m/s²:

T = 2π √(10 m / (10 m/s²))

T = 2π s

madison3395

Answer:

A. 2π s

Explanation:

Assuming the pendulum is on the Earth and g = 10m/s2, the period is 2π s, if the length is 10 m.

T = 2π √(L/g)

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