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Sodium hydroxide is extremely soluble in water. At a certain temperature, a saturated solution contains 527 g NaOH(s) per liter of solution. Calculate the molarity of this saturated NaOH(aq) solution.

Respuesta :

Answer: The molarity of solution is 13.175 M.

Explanation:

To calculate the molarity of solution, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]

We are given:

Mass of solute (sodium hydroxide) = 527 g

Molar mass of sodium hydroxide = 40 g/mol

Volume of solution = 1 L

Putting values in above equation, we get:

[tex]\text{Molarity of solution}=\frac{527g}{40g/mol\times 1L}\\\\\text{Molarity of solution}=13.175M[/tex]

Hence, the molarity of solution is 13.175 M.

We are provided the following information:

  • Solute mass (sodium hydroxide) = 527 g
  • Sodium hydroxide molar mass = 40 g/mol
  • Volume of solution= 1 L 
  • When we plug values into the equation, we get:
  • [tex]M=\frac{Mass of solute}{Molar mass* volume}\\\\\\M= \frac{527}{40*1} = 13.175M[/tex]

Thus, the molarity is calculated to be 13.175M.

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