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The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term in the parabola's equation?

The vertex of this parabola is at 4 1 When the yvalue is 0 the xvalue is 2 What is the coefficient of the squared term in the parabolas equation class=

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DeanR

This is a parabola in vertex form,

[tex]x = a(y - p)^2 + q[/tex]

a is the coefficient on y^2 we seek.  Since it's sideways we have p=-1, q=-4

[tex]x = a(y -1)^2 - 4[/tex]

When y=0,

[tex] x=a - 4 = 2[/tex]

[tex] a = 6[/tex]

Answer: A

luisejr77

Answer: Option A

Step-by-step explanation:

The shape of the vertex of a parabola is:

[tex]x = a (y-h) ^ 2 + k[/tex]

Where the point (k, h) is the vertex of the parabola and "a"  is the coefficient of the squared term.

In this case we know that the vertex of this parabola is:

(-4, -1)

Then:

[tex]h=-1[/tex] and [tex]k=-4[/tex]

So the equation is:

[tex]x = a (y+1) ^ 2 -4[/tex]

We know that whe the y-value is 0, the x-value is 2.

This mean  that:

[tex]2 = a (0+1) ^ 2 -4[/tex]

[tex]2 = a -4[/tex]

[tex]a= 6[/tex]

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