Write an equation of the parabola that has the same shape as the graph of f(x) = 8x^2, but with (6,6) as the vertex g(x)= (Simplify your answer.)

Respuesta :

Answer:

[tex]g(x) = 8(x-6)^{2} +6[/tex]

Step-by-step explanation:

General equation of a parabola:

[tex]y - y_{0} =a(x-x_{0})^{2}[/tex]

Where:

[tex]V = (x_{0} ,y_{0})[/tex] is the vertex of the parabola

a is the shape of the parabola

Known equation: [tex]f(x) = 8x^{2}[/tex]

Known information:

V = (0, 0)

a = 8

With this information we write the equation like this:

[tex]y-0 =8(x-0)^{2}[/tex]

Equation requested: g(x) = ?

Known information:

V = (6, 6)

a = 8

With this information we write the equation like this:

[tex]y-6=8(x-6)^{2}[/tex]

Then,

[tex]g(x) = 8(x-6)^{2} +6[/tex]