Respuesta :
Answer: The required value is P(A ∪ B) = 0.73.
Step-by-step explanation: Given that A and B are two mutually exclusive events where
[tex]P(A)=0.25~~~\textup{and}~~~P(B)=0.48[/tex]
We are to find the following probability :
P(A ∪ B).
We know that
the intersection of two mutually exclusive events is null event. That is,
A ∩ B = ∅ ⇒ P(A ∩ B) = 0.
From the laws of probability, we have
[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.25+0.48-0=0.73[/tex]
Thus, the required value is P(A ∪ B) = 0.73.
Answer with explanation:
It is given that, two Events , A and B are mutually exclusive.
→Pr (A ∩ B)=0
→Pr(A)=0.25
→Pr (B)= 0.48
So, Pr (A ∪ B)=Pr (A)+ Pr (B)-Pr(A∩B)
=0.25 +0.48-0
=0.73
