We are interested in p, the population proportion of all people who are currently happy with their cell phone plans. In a small study done in 2012, it was found that in a sample of 150 people, there were 90 who were happy with their cell phone plans. Using the data from this prior study, find the sample size needed to construct a 95% confidence interval for p with a margin of error of 0.025

Respuesta :

Answer:  19

Step-by-step explanation:

The formula to find the sample size is given by :_

[tex]n=p(1-p)(\dfrac{z_{\alpha/2}}{E})[/tex]

Given : Significance level :  [tex]\alpha:1-0.95=0.05[/tex]

Critical value : [tex]z_{\alpha/2}=1.96[/tex]

The estimated population proportion by using sample : [tex]p=\dfrac{90}{150}=0.6[/tex]

Margin of error : E=0.025

Now, the required sample size will be :-

[tex]n=0.6(1-0.6)(\dfrac{(1.96)}{0.025})=18.816\approx19[/tex]