If $1000 is invested for x years at 12%, compounded continuously, the future value that results is

S = 1000e^0.12x

What amount will result in 4 years? (Round your answer to the nearest cent.)

Respuesta :

Answer:1616.07

Step-by-step explanation:

Given

Principal=1000

Rate of interest =12

Time =4

[tex] Amount =Pe^{0.12x}[/tex]

[tex] A=1000e^{0.12\cdot 4} [/tex]

[tex] A=1000\times 1.61607 [/tex]

A=1616.07

Answer with explanation:

Amount =$ 1000

Time =x Years

Rate of Interest = 12 %

Value of Money after x years is given by

                          [tex]=1000e^{0.12 x}[/tex]  

Amount after 4 years is equal to

                          [tex]=1000e^{0.12\times 4}\\\\=1000 \times e^{0.48}\\\\=1000 \times (2.71828)^{0.48}\\\\=1000 \times 1.61607388\\\\=1616.0739[/tex]