Answer:
Step-by-step explanation:
[tex]A)\ m=2=\dfrac{2\cdot3}{3}=\dfrac{6}{3}<\dfrac{13}{3}\qquad\bold{NOT}\\\\B)\ m=5=\dfrac{5\cdot3}{3}=\dfrac{15}{3}>\dfrac{13}{3}\qquad\bold{YES}\\\\C)\ m=3=\dfrac{3\cdot3}{3}=\dfrac{9}{3}<\dfrac{13}{3}\qquad\bold{NOT}\\\\D)\ m=-9<\dfrac{13}{3}\qquad\bold{NOT}[/tex]