Answer: (0.3224,0.3976)
Step-by-step explanation:
Given : Sample size : n=625
Number of people check their work email when they are at home =225
The probability of people check their work email when they are at home :[tex]p=\dfrac{225}{625}=0.36[/tex]
Significance level : [tex]\alpha:1-0.95=0.05[/tex]
Critical value : [tex]z_{\alpha/2}=1.96[/tex]
The confidence interval for population proportion is given by :-
[tex]p \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.36\pm(1.96)\sqrt{\dfrac{0.36(1-0.36)}{625}}\\\\=0.36\pm0.037632\\\\=(0.322368,0.397632)\approx(0.3224,0.3976)[/tex]