A charge of 1.5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How much potential energy is stored in the capacitor? × 10–5 J

Respuesta :

Answer:

Energy stored in the capacitor is [tex]U=2.7\times 10^{-5}\ J[/tex]        

Explanation:

It is given that,

Charge, [tex]q=1.5\ \mu C=1.5\times 10^{-6}\ C[/tex]

Potential difference, V = 36 V

We need to find the potential energy is stored in the capacitor. The stored potential energy is given by :

[tex]U=\dfrac{1}{2}q\times V[/tex]

[tex]U=\dfrac{1}{2}\times 1.5\times 10^{-6}\times 36[/tex]  

U = 0.000027 J

[tex]U=2.7\times 10^{-5}\ J[/tex]

So, the potential energy is stored in the capacitor is [tex]U=2.7\times 10^{-5}\ J[/tex]. Hence, this is the required solution.

Answer:

2.7

Explanation: