Answer: The concentration of HCl comes out to be 0.718 M.
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is HCl
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=1\\M_1=?M\\V_1=25.0mL\\n_2=1\\M_2=0.188M\\V_2=95.5mL[/tex]
Putting values in above equation, we get:
[tex]1\times M_1\times 25=1\times 0.188\times 95.5\\\\M_1=0.718M[/tex]
Hence, the concentration of HCl comes out to be 0.718 M.
