Answer:
[tex]\text{sin}(x)[/tex] is an odd function.
Step-by-step explanation:
We are asked to prove whether [tex]\text{sin}(x)[/tex] is even or odd.
We know that a function [tex]f(x)[/tex] is even if [tex]f(x)=f(-x)[/tex] and a function [tex]f(x)[/tex] is odd, when [tex]f(-x)=-f(x)[/tex].
We also know that an even function is symmetric with respect to y-axis and an odd function is symmetric about the origin.
Upon looking at our attachment, we can see that [tex]\text{sin}(x)[/tex] is symmetric with respect to origin, therefore, [tex]\text{sin}(x)[/tex] is an odd function.
Answer:
sin x is an odd function.
Step-by-step explanation:
f(x) = sin x
even function are those function in which when we put x = -x the function comes out to be f(-x) = f(x)
odd functions are those functions when we put x = -x then function comes out to be f(-x) = -f(x).
so,
in sin x when put x = -x
f(-x) = sin (-x)
= -sin (x)
hence, f(-x) = - f(x)
hence sin x is an odd function.
