Options B and C,
20 jars of honey and 6 honeycombs
30 jars of honey and 9 honeycombs
Since 20/10 = 2, we need to make sure that the number of honeycombs is 3*2 = 6.
The same goes for the Option C, since 30/10 = 3, we need to make sure that 3*3 = 9.
Okay, that might have been a bad explanation.
For Option B, we know that he has 20 jars of honey, right? Since he brings 10 jars of honey for every 3 honeycombs, we divide 20 by 10 (20/10) , which gives us 2. This means that he brought 2 groups of ten jars of honey. We also know that for every group of ten jars, he brings 3 honeycombs, meaning that he brought 2 groups of three honeycombs. 3 times 2 is 6, showing that the Option B is correct. The same goes for Option C. He brought 3 groups of ten jars of honey, and 3 groups of 3 honeycombs.
[tex]\huge{\boxed{\text{Option B}}}\ \ \huge{\boxed{\text{Option C}}}[/tex]
First, we know the number of jars must be a multiple of [tex]10[/tex] and the number of honeycombs must be a multiple of [tex]3[/tex].
We can remove option A because [tex]18[/tex] is not a multiple of [tex]10[/tex] and [tex]5[/tex] is not a multiple of [tex]3[/tex].
We can remove option D because [tex]10[/tex] is not a multiple of [tex]3[/tex].
We can remove option E because [tex]16[/tex] is not a multiple of [tex]3[/tex].
This leaves us with options [tex]\boxed{\text{B}}[/tex] and [tex]\boxed{\text{C}}[/tex].
