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Calculate the solubility (in g/L) of silver carbonate in water at 25°C if the Ksp for Ag2CO3 is 8.4 x 10-12, A) 8.0 x 10-4 g/L B) 3.5 x 10-2 g/L C)4.4 × 10-2g/L D) 5.6 x 10-2 g/L

Respuesta :

Answer:

S = 5.6 E-2 g / L

Explanation:

  • Ag2CO3 ⇔ 2Ag + CO3

⇒         S                 2S       S

⇒ Kps = 2S*S = 2S² = 8.4 E-12

⇒ S² = 8.4 E-12 / 2

⇒ S² = 4.2 E-12

⇒ S = √4.2 E-12

⇒ S = 2.05 E-6 mmol / mL

⇒ S = 2.05 E-6 mmol / mL * 0.001 mol / mmol * 275.7453 g Ag2CO3 / mol * 1000mL / L

⇒S = 5.651E-2 g / L

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