Answer: The final temperature is [tex]155.2^oC[/tex]
Explanation:
To calculate the final temperature, we use the equation:
[tex]Q=mc\Delta T[/tex]
where,
Q = heat absorbed = 250 J
m = Mass of the substance = 15 g
c = specific heat capacity of water = 0.128 J/g.°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(T_2-25^oC)[/tex]
Putting values in above equation, we get:
[tex]250J=15g\times 0.128J/g.^oC\times (T_2-25)\\\\T_2=155.2^oC[/tex]
Hence, the final temperature is [tex]155.2^oC[/tex]
