A 0.20 M solution of MgSO, has an observed osmotic pressure of 7.6 atm at 25°C. Determine the observed van't Hoff factor i for this experiment a) 1.6 b) 19 c)0.31 d)1.8 e) 2.0

Respuesta :

Answer: The correct answer is Option a.

Explanation:

To calculate the Vant't Hoff factor, we use the equation for osmotic pressure, which is:

[tex]\pi=icRT[/tex]

where,

[tex]\pi[/tex] = osmotic pressure of the solution = 7.6 atm

i = Van't hoff factor = ?

c = concentration of [tex]MgSO_4[/tex] = 0.20 mol/L

R = Gas constant = [tex]0.0820\text{ L atm }mol^{-1}K^{-1}[/tex]

T = temperature of the solution = [tex]25^oC=[273+25]=298K[/tex]

Putting values in above equation, we get:

[tex]7.6atm=i\times 0.20mol/L\times 0.0820\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\i=1.6[/tex]

Hence, the correct answer is Option a.