Answer: The specific heat capacity of the metal is [tex]0.24J/g.^oC[/tex]
Explanation:
To calculate the specific heat of metal, we use the equation:
[tex]Q=mc\Delta T[/tex]
where,
Q = heat absorbed = 1500 J
m = Mass of the substance = 250 g
c = specific heat capacity of water = ? J/g.°C
[tex]\Delta T[/tex] = change in temperature = [tex]25^oC[/tex]
Putting values in above equation, we get:
[tex]1500J=250g\times c\times 25^oC\\\\c=0.24J/g.^oC[/tex]
Hence, the specific heat capacity of the metal is [tex]0.24J/g.^oC[/tex]
