Respuesta :
Answer:
The salt is barium chloride.
Explanation:
[tex]BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX[/tex]
Moles of barium sulfate =[tex]\frac{11.21 g}{233.38 g/mol}=0.0480 mol[/tex]
According to reaction, 1 mol of barium sulfate is produced from 1 mol of [tex]BaX_2[/tex].
Then 0.0480 moles will be produced from:
[tex]\frac{1}{1}\times 0.0480 mol=0.0480 mol[/tex] of [tex]BaX_2[/tex].
Mass of [tex]BaX_2[/tex] used = 10.00 g
Moles of [tex]BaX_2[/tex] =\frac{10.00 g}{\text{Molar mass}}[/tex]
[tex]0.0480 mol=\frac{10.00}{\text{Molar mass}}[/tex]
Molar mass of [tex]BaX_2[/tex] = 208.33 g/mol
The nearest answer to our answer is [tex]BaCl_2=208.2 g/mol[/tex].
The correct answer barium chloride with molar mass of 208.2 g/mol.
