Respuesta :
Answer: The molality of solution is 0.740 m.
Explanation:
To calculate the mass of solvent (water), we use the equation:
[tex]Density=\frac{Mass}{Volume}[/tex]
Volume of water = 750 mL
Density of water = 1 g/mL
Putting values in above equation, we get:
[tex]1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g[/tex]
To calculate the molality of solution, we use the equation:
[tex]Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}[/tex]
Where,
[tex]m_{solute}[/tex] = Given mass of solute [tex](C_6H_{12}O_6)[/tex] = 100.0 g
[tex]M_{solute}[/tex] = Molar mass of solute [tex](C_6H_{12}O_6)[/tex] = 180 g/mol
[tex]W_{solvent}[/tex] = Mass of solvent (water) = 750 g
Putting values in above equation, we get:
[tex]\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m[/tex]
Hence, the molality of solution is 0.740 m.
