Answer:
41.66 mL of 12.0 M sulfuric acid are needed.
Explanation:
Concentration of sulfuric acid solution taken =[tex]M_1=12.0M[/tex]
Volume of the 12.0 M Solution = [tex]V_1[/tex]
Concentration of required solution = [tex]M_2=1.00M[/tex]
Volume of required 1.00 M solution = [tex]V_2=500.0 mL[/tex]
[tex]M_1V_1=M_2V_2[/tex] (Dilution)
[tex]V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL[/tex]
41.66 mL of 12.0 M sulfuric acid are needed.
The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.
