Respuesta :
Answer: The molarity of NaOH solution is 0.096 M.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of KHP = 0.835 g
Molar mass of KHP = 204.2 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of KHP}=\frac{0.835g}{204.2g/mol}=0.00408mol[/tex]
For the given chemical reaction:
[tex]KHP+NaOH\rightarrow NaKP+H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of KHP reacts with 1 mole of NaOH.
So, 0.00408 moles of KHP will react with = [tex]\frac{1}{1}\times 0.00408=0.00408mol[/tex] of NaOH.
To calculate the molarity of NaOH, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
We are given:
Moles of NaOH = 0.00408 moles
Volume of solution = 42.52 mL = 0.04252L (Conversion factor: 1L = 1000 mL)
Putting values in above equation, we get:
[tex]\text{Molarity of NaOH }=\frac{0.00408mol}{0.04252L}=0.096M[/tex]
Hence, the molarity of NaOH solution is 0.096 M.
