Answer : The volume of calcium hydroxide is, 32.89 ml
Explanation :
Using neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1[/tex] = basicity of an acid = 1
[tex]n_2[/tex] = acidity of a base = 2
[tex]M_1[/tex] = concentration of hydrobromic acid = 0.389 M
[tex]M_2[/tex] = concentration of calcium hydroxide = 0.0887 M
[tex]V_1[/tex] = volume of hydrobromic acid = 15 ml
[tex]V_2[/tex] = volume of calcium hydroxide = ?
Now put all the given values in the above law, we get the volume of calcium hydroxide.
[tex]1\times 0.389M\times 15ml=2\times 0.0887M\times V_2[/tex]
[tex]V_2=32.89ml[/tex]
Therefore, the volume of calcium hydroxide is, 32.89 ml
