Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and oxalic acid (H2C2O4) are combined. Assume excess base. Use the pull-down boxes to specify states such as (aq) or (s).

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InesWalston InesWalston · Answer 1 · 2019-08-13T06:05:55+02:00

Answer:

Oxalic acid is a dicarboxylic acid and forms sodium salt with NaOH and water

Explanation:

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okpalawalter8 okpalawalter8 · Answer 2 · 2020-04-15T03:59:43+02:00

Answer:

The net ionic equation for the overall reaction is

[tex]H_2C_2O_4{(aq)} + 2OH^-_{(aq)} ----> C_2O_4^{2-}_{(aq)} + 2H_2O_{(l)}[/tex]

Explanation:

The molecular formula for sodium hydroxide is [tex]NaOH[/tex] while the molecular formula for oxalic acid is given as ([tex]H_2 C_2 O_4[/tex])

Now the balanced chemical equation for this reaction is

[tex]H_2C_2 O_4_{(aq)} + 2NaOH_{(aq)} ----> Na_2C_2O_4_{(aq)} + 2H_2O_{(l)}[/tex]

The procedure for the ionic equation is

[tex]H_2 C_2O_4 _{(aq)} + 2 Na^+ _{(aq)} + 2OH^-_{(aq)} ---->2Na^+ _{(aq)} + C_2O_4^{2- }_{(aq)} + 2H_2O_{(l)}[/tex]

Here [tex]Na^+[/tex] is the sodium ion

[tex]OH^-[/tex] is the hydroxide ion

[tex]C_2O_4^{2-}[/tex] is the oxalate ion

Note: The dissociation of oxalic equation is not complete because it is a weak acid

Looking at this equation we see that [tex]Na^+[/tex] is common on both sides of the equation so we cancel it out so the equation becomes

[tex]H_2C_2O_4{(aq)} + 2OH^-_{(aq)} ----> C_2O_4^{2-}_{(aq)} + 2H_2O_{(l)}[/tex]