Solve the following: x – 2= 7
Answer:
Given, x -2 = 7
=> x – 2 + 2= 7 + 2 [Adding 2 both sides]
=> x = 9
Question 2:
Solve of the following: y + 3 = 10
Solution:
Given, y + 3 = 10
=> y + 3 – 3 = 10 – 3 [subtracting 3 on both side]
=> y = 7
Question 3:
Solve the following: 6 = z + 2
Answer:
Given, 6 = 2 + z
=> 6 – 2 = z + 2 – 2 [Subtracting 2 both sides]
=> 4 = z
=> z = 4
Question 4:
Solve the following: 3/7 + x = 17/7
Answer:
Given, 3/7 + x = 17/7
=> 3/7 + x – 3/7 = 17/7 – 3/7 [Subtracting 3/7 on both sides]
=> x = (17 - 3)/7
=> x = 14/7
=> x = 2
Question 5:
Solve the following: 6x = 12
Answer:
Given, 6x = 12
=> 6x/6 = 12/6 [Dividing 6 on both side]
=> x = 2
Question 6:
Solve the following: t/5 = 10
Answer:
Given, t/5 = 10
=> t/5 * 5 = 10 * 5 [Multiply by 5 on both side]
=> t = 50
Question 7:
Solve the following: 2x/3 = 18
Answer:
Given, 2x/3 = 18
=> 2x = 3 * 18
=> 2x = 54
=> x = 54/2
=> x = 27
Question 8:
Solve the following: 1.6 = y/1.5
Answer:
Given, 1.6 = y/1.5
=> y = 1.6 * 1.5
=> y = 2.40
Question 9:
Solve the following: 7x – 9 = 16
Answer:
Given, 7x – 9 = 16
=> 7x = 16 + 9
=> 7x = 25
=> x = 25/7
Question 10:
Solve the following: 14y – 8 = 13
Answer:
Given, 14y – 8 = 13
=> 14y = 13 + 8
=> 14y = 21
=> y = 21/14
=> y = 3/2 [21 and 14 are divided by 7]
Question 11:
Solve the following: 17 + 6p = 9
Answer:
Given, 17 + 6p = 9
=> 6p = 9 – 17
=> 6p = -8
=> p = -8/6
=> p = -4/3 [8 and 6 are divided 2]
Answer = A Linear Equation is an algebraic equation composed of a constant (e.g. x = 3) or a variable to the power of 1 (e.g. 2a + 3 = 13).
Remember that 2a means 2 × a.
Solving an equation is to figure out what number is represented by the variable. For example, in the equation 2a + 3 = 13, the variable a is 5. That’s what I can
