this table gives a few (x,y) pairs of a line in the coordinate plane.
what is the y intercept of the line?

Answer:
y intercept is -23
Step-by-step explanation:
Here we are given three coordinates and are asked to find y intercept of the line passing through these points.
We thus find the equation of this line by two point form
the form says
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
Here (x1,y1) = ( -36 , 1 )
and (x2,y2) = ( 13,-54)
Substituting the values we get
(y-1)(x+36)=(1-13)/(-36-(-54))
(y-1)(x+36)=(-12)/(-36+54)
(y-1)(x+36)=(-12)/(18)
y-1=-2/3 ( x+36)
In order to determine the y intercept we are required to leep x = 0 in above equation and solve for y
y-1 = -2/3 (0+36 )
y-1= (-2/3) x (36 )
y-1 = -2 x 12
y-1 = -24
adding 1 on both hand sides
y = -24 +1
y=-23
Answer:
y = -23
Step-by-step explanation:
Equation of line in intercept form is y = mx + c
Where m = slope of the line
and c = y-intercept
Now slope m = [tex](\frac{y-y'}{x-x'} )[/tex] where (x, y) and (x',y') are the points lying on the line
If two points are (-72, 25) and (-54, 113)
so m = [tex](\frac{25-13}{-72-54} )[/tex]
= [tex]\frac{(-12}{18}[/tex] = [tex]\frac{(-2)}{3} )[/tex]
Now equation of the line will be y = [tex](\frac{-2}{3}x+c[/tex]
This line passes through (-36, 1)
So 1 = [tex]\frac{(-2)}{3} )[/tex] × (-36) + c
1 = 2 × (+12) + c
1 + +24 + c ⇒ c = 1 -24
= -23